Forumophilia - 18 Years Online!
Djnx
Respected Poster
fantailedalbi
Respected Poster
ws777ot - I think the difference in your post count is due to the time-warp continuity difference which runs in this forum.
2 days ago I received a pm from SD which was a reply to a message I sent last August. After enquiry I found out that he'd only just received the pm, 9 months after I posted it.
So your remaining posts are out there somewhere, possibly in Star Trek land, waiting to arrive.
Albi
2 days ago I received a pm from SD which was a reply to a message I sent last August. After enquiry I found out that he'd only just received the pm, 9 months after I posted it.
So your remaining posts are out there somewhere, possibly in Star Trek land, waiting to arrive.
Albi
ramblin'man
ws777ot wrote:
Checked my own posts, and yeah, I'm missing a few too. I'm blaming Gnome, somehow he managed to sneak in and steal them.
Wassamatter, you can't walk in a perfect arc? We all do it so well all the time, or when we're driving ... you drive a kilometer east/west, and guess what: you're curving. Slightly. UNLESS ... you're walking exactly along the Equator.
Naturally, a "straight" line is straight in a curvilinear sense.
Regarding your walking problem, well, get yourself a length of rope/string that is 1 KM long. Tie it to the flag at the north pole ... then walk SOUTH for the length of the rope ... then walk WEST keeping that rope taut the whole way ... and so on. Viola!
Dorky'Man
If you start at the North Pole and walk 1km South...OK
Then if you take a compass bearing and walk in a straight line West (or East) then you would be walking away from the North Pole as soon as you started to move? In order to arrive at a point to enable you to walk one 1km back to the North Pole then you would have to constantly correct your course ie walk West (or East) in an arc....not easy to do eh?
How about this one?
My post count shows (at present) 1708....BUT when I look at my profile and look at the 'find all posts by' ie get the result 1714. Where have the 6 missing posts gone?
Then if you take a compass bearing and walk in a straight line West (or East) then you would be walking away from the North Pole as soon as you started to move? In order to arrive at a point to enable you to walk one 1km back to the North Pole then you would have to constantly correct your course ie walk West (or East) in an arc....not easy to do eh?
How about this one?
My post count shows (at present) 1708....BUT when I look at my profile and look at the 'find all posts by' ie get the result 1714. Where have the 6 missing posts gone?
Checked my own posts, and yeah, I'm missing a few too. I'm blaming Gnome, somehow he managed to sneak in and steal them.
Wassamatter, you can't walk in a perfect arc? We all do it so well all the time, or when we're driving ... you drive a kilometer east/west, and guess what: you're curving. Slightly. UNLESS ... you're walking exactly along the Equator.
Naturally, a "straight" line is straight in a curvilinear sense.
Regarding your walking problem, well, get yourself a length of rope/string that is 1 KM long. Tie it to the flag at the north pole ... then walk SOUTH for the length of the rope ... then walk WEST keeping that rope taut the whole way ... and so on. Viola!
Dorky'Man
gnoga
Poster
a "straight line with compass is always a curve, because we are living on ball 
.. still waiting on the next question ...
i will make my own.
- don't google
- don't calculate
only try to guess the answer. post only your guess the next 24h, no calculation, to let the other guess too.
i take the rope from the last posting, ok no, mine is much longer. I bought the rope that it should fits exact around the equator of our earth, and its endless (a ring). ( My equator is "ideal", no hills or valley. its an perfect ball. )
but the dealer made a mistake and cut 1m to much, so the length is 1m to long, thererfore its a little to loose.
This rope is made out of a special stuff, files with helium so that it hover.
now the Question, how much is the rope hover over the earth?
a) you can put no hair under it
b) you can put an hair under it
c) to less, that a ant can pass under it, but hair is OK.
d) enough that the ant can crawl under it
e) a mouse can crawl under it
f) a hare can crawl under it
or just say how much mm you think is between the rope and the earth.
(@threadstarter, if you don't like that i make this question i will post it in an other thread)
.. still waiting on the next question ...
i will make my own.
- don't google
- don't calculate
only try to guess the answer. post only your guess the next 24h, no calculation, to let the other guess too.
i take the rope from the last posting, ok no, mine is much longer. I bought the rope that it should fits exact around the equator of our earth, and its endless (a ring). ( My equator is "ideal", no hills or valley. its an perfect ball. )
but the dealer made a mistake and cut 1m to much, so the length is 1m to long, thererfore its a little to loose.
This rope is made out of a special stuff, files with helium so that it hover.
now the Question, how much is the rope hover over the earth?
a) you can put no hair under it
b) you can put an hair under it
c) to less, that a ant can pass under it, but hair is OK.
d) enough that the ant can crawl under it
e) a mouse can crawl under it
f) a hare can crawl under it
or just say how much mm you think is between the rope and the earth.
(@threadstarter, if you don't like that i make this question i will post it in an other thread)
baralis
Poster
gnoga - reckon the answer is around 16mm (if I can remember the radius of the earth right) - so just enough for an ant to crawl under. Surprising really and I wouldn't be too amazed if there was an error in my working. 
gnoga
Poster
ramblin'man
gnoga wrote:
No worries Gnoga about your problem, mine can wait. Although now I'm going to have to call myself "Threadstartin'Man".
JK, please ... call me RM. Or, shithead. Or, assface. Or fuck-for-brains. Or anything along those lines.
Incidentally, the earth isn't a ball of course. Its kinda shaped like a rugby or Aussie football, sort of an Oblong or Oblate Spheroid -- which makes me think of another stupid trivia fact (hello fantailedalbi).
But I digress, back to your problem ... heh ... that's a good one. There's a really cool thing regarding this problem, but I'll let you reveal it. Of course, this is all assuming that the distance its hovering above the equator is uniform everywhere and can't change. If that's the case ...
How many mm will the space under the rope be? Without using a calculator, should be 1000/(2*PI), or a little less than 160 mm, so I'm going for the Wascally Wabbit to squeeze under! Hare's to ya. In fact, I'd bet my own 2 Oblate Spheroids on it.
RabbitHuntin'Man
a "straight line with compass is always a curve, because we are living on ball
.. still waiting on the next question ...
i will make my own.
- don't google
- don't calculate
only try to guess the answer. post only your guess the next 24h, no calculation, to let the other guess too.
i take the rope from the last posting, ok no, mine is much longer. I bought the rope that it should fits exact around the equator of our earth, and its endless (a ring). ( My equator is "ideal", no hills or valley. its an perfect ball. )
but the dealer made a mistake and cut 1m to much, so the length is 1m to long, thererfore its a little to loose.
This rope is made out of a special stuff, files with helium so that it hover.
now the Question, how much is the rope hover over the earth?
a) you can put no hair under it
b) you can put an hair under it
c) to less, that a ant can pass under it, but hair is OK.
d) enough that the ant can crawl under it
e) a mouse can crawl under it
f) a hare can crawl under it
or just say how much mm you think is between the rope and the earth.
(@threadstarter, if you don't like that i make this question i will post it in an other thread)
.. still waiting on the next question ...
i will make my own.
- don't google
- don't calculate
only try to guess the answer. post only your guess the next 24h, no calculation, to let the other guess too.
i take the rope from the last posting, ok no, mine is much longer. I bought the rope that it should fits exact around the equator of our earth, and its endless (a ring). ( My equator is "ideal", no hills or valley. its an perfect ball. )
but the dealer made a mistake and cut 1m to much, so the length is 1m to long, thererfore its a little to loose.
This rope is made out of a special stuff, files with helium so that it hover.
now the Question, how much is the rope hover over the earth?
a) you can put no hair under it
b) you can put an hair under it
c) to less, that a ant can pass under it, but hair is OK.
d) enough that the ant can crawl under it
e) a mouse can crawl under it
f) a hare can crawl under it
or just say how much mm you think is between the rope and the earth.
(@threadstarter, if you don't like that i make this question i will post it in an other thread)
No worries Gnoga about your problem, mine can wait. Although now I'm going to have to call myself "Threadstartin'Man".
JK, please ... call me RM. Or, shithead. Or, assface. Or fuck-for-brains. Or anything along those lines.
Incidentally, the earth isn't a ball of course. Its kinda shaped like a rugby or Aussie football, sort of an Oblong or Oblate Spheroid -- which makes me think of another stupid trivia fact (hello fantailedalbi).
But I digress, back to your problem ... heh ... that's a good one. There's a really cool thing regarding this problem, but I'll let you reveal it. Of course, this is all assuming that the distance its hovering above the equator is uniform everywhere and can't change. If that's the case ...
How many mm will the space under the rope be? Without using a calculator, should be 1000/(2*PI), or a little less than 160 mm, so I'm going for the Wascally Wabbit to squeeze under! Hare's to ya. In fact, I'd bet my own 2 Oblate Spheroids on it.
RabbitHuntin'Man
baralis
Poster
ramblin'man wrote:
How many mm will the space under the rope be? Without using a calculator, should be 1000/(2*PI), or a little less than 160 mm, so I'm going for the Wascally Wabbit to squeeze under!
Bugger - that's what I meant! Somehow I went from 0.16m to 16mm...
How many mm will the space under the rope be? Without using a calculator, should be 1000/(2*PI), or a little less than 160 mm, so I'm going for the Wascally Wabbit to squeeze under!
Bugger - that's what I meant! Somehow I went from 0.16m to 16mm...
gnoga
Poster
ramblin'man
gnoga wrote:
Yep, that's what I meant by the cool thing regarding your problem. It doesn't matter what size "ball" you start with ... tennis ball ... earth ... Britney Spears' Pork-Rind-digesting stomach ... the moon ... it doesn't matter. You add a meter to the length of the rope and the answer doesn't change.
Great stuff, as I bet there were oodles of Engineering types out there (you know who you are) who were calculating using the circumference and radius of the earth, worrying about how many digits of PI to use, etc.
For clarity and in case anyone is interested, here's a way to look at the problem.
Let R = radius of earth in meters
Let G = distance Gnoga's rope hovers above the equator.
Then the circumference of the earth is 2*PI*R, and the length of Gnoga's rope is therefore 2*PI*R + 1
So G = radius of Gnoga's circle minus radius of Earth
So G = (2*PI*R + 1)/(2*PI) - R
And G = (2*PI*R)/(2*PI) + 1/(2*PI) - R
And G = R + 1/(2*PI) - R
And G = 1/(2*PI)
To get mm instead of meters, use 1000, etc etc.
Stay tuned for the next one, I'll try to whip up something more exciting than my "infinite series" problem I had planned.
RM
what i find fantastic, is, it don't care if you use the earth, the sun or the moon, ... or just a marble, its always the same.
if you take a rope with 1m and make a circle it has the same radius.
if you take a rope with 1m and make a circle it has the same radius.
Yep, that's what I meant by the cool thing regarding your problem. It doesn't matter what size "ball" you start with ... tennis ball ... earth ... Britney Spears' Pork-Rind-digesting stomach ... the moon ... it doesn't matter. You add a meter to the length of the rope and the answer doesn't change.
Great stuff, as I bet there were oodles of Engineering types out there (you know who you are) who were calculating using the circumference and radius of the earth, worrying about how many digits of PI to use, etc.
For clarity and in case anyone is interested, here's a way to look at the problem.
Let R = radius of earth in meters
Let G = distance Gnoga's rope hovers above the equator.
Then the circumference of the earth is 2*PI*R, and the length of Gnoga's rope is therefore 2*PI*R + 1
So G = radius of Gnoga's circle minus radius of Earth
So G = (2*PI*R + 1)/(2*PI) - R
And G = (2*PI*R)/(2*PI) + 1/(2*PI) - R
And G = R + 1/(2*PI) - R
And G = 1/(2*PI)
To get mm instead of meters, use 1000, etc etc.
Stay tuned for the next one, I'll try to whip up something more exciting than my "infinite series" problem I had planned.
RM
baralis
Poster
ramblin'man wrote:
Great stuff, as I bet there were oodles of Engineering types out there (you know who you are) who were calculating using the circumference and radius of the earth, worrying about how many digits of PI to use, etc.
"Engineering" types? I've never been so insulted in my life
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
Great stuff, as I bet there were oodles of Engineering types out there (you know who you are) who were calculating using the circumference and radius of the earth, worrying about how many digits of PI to use, etc.
"Engineering" types? I've never been so insulted in my life
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
ramblin'man
baralis wrote:
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money. Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
"Engineering" types? I've never been so insulted in my life
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money.
Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
melmac
Good Poster
ramblin'man wrote:
Without using brute force, my guess is that all lockers are closed.
But I'm dying to know the real answer and how to get to it
Melmac
baralis wrote:
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money. Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
"Engineering" types? I've never been so insulted in my life
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money.
Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
Without using brute force, my guess is that all lockers are closed.
But I'm dying to know the real answer and how to get to it
Melmac
ramblin'man
melmac wrote:
Hmmmm. Well Locker #1 is open, since Girl #1 is the only one who touches it (and opens it).
Locker #2 will be closed, since #1 opens it, #2 closes it, then no one else touches it. Locker #3 will be closed, since #1 opens it, #2 skips it, and #3 closes it. Locker #4 will be open, since #1 opens it, #2 closes it, #3 skips it, #4 opens it, and no one else touches it.
#1 - Open
#2 - Closed
#3 - Closed
#4 - Open
How about the rest? You can see that using brute force would take an extremely long time. However, yep, there just might be a patterrn.
RM
ramblin'man wrote:
Without using brute force, my guess is that all lockers are closed.
But I'm dying to know the real answer and how to get to it
Melmac
baralis wrote:
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money. Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
"Engineering" types? I've never been so insulted in my life
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
But yes, as you can see from my earlier reply I did indeed calculate using the earth's radius then added 1 and did it again to get the difference - doh!
No worries, you can get the right answer by doing the correct calculations of course. And hey, "Engineering" types typically make good money.
Even I did my stint in Corporate America doing "applied" math.
However, you may not want to use "brute force" on the next problem, unless you have a lot of time.
Next Problem:
Behind the scenes at GS's "Finishing School for Funs Models" in Kiev ...
There are 100 Funs models, each having a number from 1-100.
There are 100 closed lockers in a hallway.
Model #1 goes down the hall and opens every locker.
Model #2 goes down the hall and closes locker #2, #4, #6, and every other locker.
Model #3 goes down the hall and closes locker #3, then opens locker #6, closes #9, opens #12, and "changes the state" of every locker having a number which is a multiple of 3.
Model #4 goes down the hall and changes the state of every 4th locker.
And so on. Etc etc. Blah blah blah. Yadda yadda yadda...
Model #100 goes down the hall and changes the state of Locker #100.
After they're all done, which lockers are open? And can you tell why?
RM
Without using brute force, my guess is that all lockers are closed.
But I'm dying to know the real answer and how to get to it
Melmac
Hmmmm. Well Locker #1 is open, since Girl #1 is the only one who touches it (and opens it).
Locker #2 will be closed, since #1 opens it, #2 closes it, then no one else touches it. Locker #3 will be closed, since #1 opens it, #2 skips it, and #3 closes it. Locker #4 will be open, since #1 opens it, #2 closes it, #3 skips it, #4 opens it, and no one else touches it.
#1 - Open
#2 - Closed
#3 - Closed
#4 - Open
How about the rest? You can see that using brute force would take an extremely long time. However, yep, there just might be a patterrn.
RM
baralis
Poster
RM,
I'm going to suggest that after the models have done their stuff they will have left the following lockers open:
1, 4, 16, 25, 36, 49, 64, 81, 100
The reason being that each locker needs to have an odd number of visitors in order for it to stay open. For the general case, locker N is visited by:
girl 1 and girl N (always) [for locker 1 this is the same girl]
if the locker is visited by girl X then it must also be visited by girl Y (where Y=N/X).
Therefore the only way that a locker can have an odd number of visits is if at some point X=Y (i.e. it is a square number).
That's my logic anyway! Phew - I don't normally come on here to exercise the largest organ in the body (just the second largest )
I'm going to suggest that after the models have done their stuff they will have left the following lockers open:
1, 4, 16, 25, 36, 49, 64, 81, 100
The reason being that each locker needs to have an odd number of visitors in order for it to stay open. For the general case, locker N is visited by:
girl 1 and girl N (always) [for locker 1 this is the same girl]
if the locker is visited by girl X then it must also be visited by girl Y (where Y=N/X).
Therefore the only way that a locker can have an odd number of visits is if at some point X=Y (i.e. it is a square number).
That's my logic anyway! Phew - I don't normally come on here to exercise the largest organ in the body (just the second largest
)